This simple math riddle is stumping the internet — see if you can solve it
A man buys a horse for $60. He sells the horse for $70. He then buys the horse back for $80. And he sells the horse again for $90. In the end, how much money did the man make or lose? Or did he break even?
Answers in the Mumsnet thread ranged from making $10, $20 and even $30, to breaking even. So what’s the solution?
The solution is given below;
What seems to be throwing people off is the fact that the man sells the horse for $70 and then buys it back for $80, making it look like he spent 10 more dollars. But the correct way to solve the problem is to think of the two transactions as separate: -60 + 70 = 10 and -80 + 90 = 10.
The man makes $10 with each sale, therefore he earns a total of $20.
This math challenge is meant for 10-year-olds – but most adults can’t solve it
These are old classic mathematical problems. When you were in middle or high school.
These tests are more fun when you find yourself trying to remember the math you learned as a child.
Okay, here comes the challenge.
Can you figure out the solution for this mathematics quiz – without a calculator?
Ready to give it it a try? Take a look at this math problem and see if you can come up with an answer.
It may look complicated but as soon as you figured out what you should need to do, it is just a walk in the park!
Have you come up with an answer?
If you get 11, then congratulations! 11 is the correct answer.
If you did not get 11, do not worry. We can take a look at how to solve the math problem.
The rule is to apply PEMDAS in the above math task. PEMDAS is an acronym for Parentheses, Exponents, Multiplication, Division, Addition, and Subtraction.
This rule dictates that you need to solve the equation in the parentheses first.
This means that you will need to solve (12 ÷ 4 + 1) = 4 first.
Then, you can move on to solve the multiplication operation, which is 1 x 4, followed by the subtraction, 15 – 4 = 11.
It is okay if you did not get the answer right. You can always keep this rule in mind and apply it when you encounter a new math problem in the future!